For the latest stable version, please use Spring Framework 6.2.0!

Constructors

You can invoke constructors by using the new operator. You should use the fully qualified class name for all types except those located in the java.lang package (Integer, Float, String, and so on). The following example shows how to use the new operator to invoke constructors:

  • Java

  • Kotlin

Inventor einstein = p.parseExpression(
		"new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German')")
		.getValue(Inventor.class);

// create new Inventor instance within the add() method of List
p.parseExpression(
		"Members.add(new org.spring.samples.spel.inventor.Inventor(
			'Albert Einstein', 'German'))").getValue(societyContext);
val einstein = p.parseExpression(
		"new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German')")
		.getValue(Inventor::class.java)

// create new Inventor instance within the add() method of List
p.parseExpression(
		"Members.add(new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German'))")
		.getValue(societyContext)