This version is still in development and is not considered stable yet. For the latest stable version, please use Spring Framework 6.2.1!

Constructors

You can invoke constructors by using the new operator. You should use the fully qualified class name for all types except those located in the java.lang package (Integer, Float, String, and so on). Varargs are also supported.

The following example shows how to use the new operator to invoke constructors.

  • Java

  • Kotlin

Inventor einstein = parser.parseExpression(
	"new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German')")
		.getValue(Inventor.class);

// create new Inventor instance within the add() method of List
parser.parseExpression(
	"Members.add(new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German'))")
		.getValue(societyContext);
val einstein = parser.parseExpression(
	"new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German')")
		.getValue(Inventor::class.java)

// create new Inventor instance within the add() method of List
parser.parseExpression(
	"Members.add(new org.spring.samples.spel.inventor.Inventor('Albert Einstein', 'German'))")
		.getValue(societyContext)